Which of the following molecules would have t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In $O_2$ ($16$ electrons),the molecular orbital configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi

Vedclass · Accepted Answer

$O_2$

Vedclass · Answer

(C) In $O_2$ ($16$ electrons),the molecular orbital configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1$. $sp$ mixing is generally significant for molecules with $14$ or fewer electrons (like $B_2, C_2, N_2$). For $O_2$,the energy of $2s$ and $2p$ orbitals is sufficiently different that $sp$ mixing is negligible. Even if $sp$ mixing were considered,the magnetic nature of $O_2$ (paramagnetic due to two unpaired electrons in $\pi^*$ orbitals) remains unchanged because the filling order of the higher energy orbitals is not affected by $sp$ mixing in this case.

Which of the following molecules would have the same magnetic nature regardless of whether $sp$ mixing is operative or not?

Similar Questions

Which of the following is not paramagnetic?

The increasing order of bond order of $O_2, O_2^+, O_2^-$,and $O_2^{2-}$ is:

During the change of $O_{2}$ to $O_{2}^{-}$,the incoming electron goes to the orbital:

According to $MO$ theory,the bond orders for $O_2^{2-}$,$CO$,and $NO^{+}$ respectively,are:

In which of the following processes,the bond order increases and paramagnetic character changes to diamagnetic one?

Vedclass Test Series

Exam Paper Generator

Online Exam Module